How to make a PHP exploit in the shell of a shell script

An exploit that lets a malicious program send commands to a remote host is one of the simplest ways to get a remote access system (RAS) to open a backdoor.

The idea is simple enough: Put a shellscript into a text file that the RAS can read and execute on its own.

Unfortunately, shell scripts are a lot more difficult to write and read than they seem. 

For a more technical explanation of how this works, we’ll use a simple PHP script to create a backdoor in the same way as an attacker would create a malicious website.

The script is called and it will create a shell that the RAS can then use to run commands to remotely exploit a web server, steal data, and then send the stolen data to a web browser on the victim’s system.

The attacker is able to get the shell to open up a backdoor on a target system and take advantage of a bug in the operating system to take advantage of the remote access feature to open the backdoor.

In the example below, I’ve added a check to ensure that the shell is only executed once per request.

This ensures that the script can be easily reused.

Note: You can easily test this by typing the script and running it against your web server.

The output of shows that the bash shell was opened on February 26, 2018, which was just a few days after the last update of the Shellshock vulnerability.

The shellcode is very simple and straightforward to write, which makes it easy to copy and paste into your own shell scripts.

Let’s start with the script.

The following section explains how to use the shell script to exploit a remote system. 

The script will open a shell on the localhost address (hostname), which will allow the attacker to send commands.

To make it easier to test the script, I’ll just assume that the user has administrator privileges.

To set this up, type: $shell = getpwnam -u username # The shell prompt will be something like this: $ shell # The -u option will open the login shell for root.

To open the shell, type the following commands: $user = login $shell # Enter the user name and password to the shell.

$shell -u user # The user name should be the same as the one used for the shell prompt.

# You can now login with the username and password.

To exit the shell from the login prompt, type exit.

# The output shows that I successfully logged in.

The user is root.

So we’re done!

I hope you enjoy this easy way to take a shell over the web and use it to launch malware.

It’s also possible to run this script from a different location, for example, from a local filesystem, or on a USB stick.

In this case, the script will create another shell for the user and then execute the shell code from the local filesystem. 

To get started, type in: $ user -s $ shell -p myphp # The username and the password should be identical to the ones used for login and shell prompt # and the shell will open.

To login, type ‘bash’ or ‘shell’ (without quotes).

If the shell doesn’t open, the user will have no privileges.

$ user login This will login you into the shell on localhost.

The localhost host name is displayed on the screen.

Now, let’s test the exploit. 

I have set up the shell in myphp/myphp/shell.php to be executed once on every request.

In my file, I also added the following line to check for the bash prompt before executing the script: if (isset($_GET[‘bash’])) { print ‘shell not found’; exit; } Next, let me open a terminal and run the script against my local server. 

Here is the output from the bash script. 

(This is a basic shell script that uses the -u flag to open login shell.

This will create and execute a shell for me.) 

The shell command will execute and the result of the shell command is printed on the output.

The next line shows that my php shell is running, which is great because I can run arbitrary code from it and use the same shell to execute code from any remote host.

Let me run the code again. 

#!/usr/bin/env php # The code in my php script is available at # If the bash Prompt is not present, the shell won’t open # and an error is raised.

If the prompt is present, then the shell does open.

if ($_GET[“bash”]==”bash”) { # This is the Bash prompt, as you can see on the terminal # prompt is the text used for executing the shell # command. if (($_


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